嵌套数组的条件检查

Question

I've got the following snippet to dump some info on the screen:

for ($i=0; $i < 60; $i++) {
  echo 'output: '.$array[$i]['options'][0]."<br />";
  echo 'output: '.$array[$i]['options'][4]."<br />";
}

which outputs the following:

output: Lorem ipsum
output: 1
output: dolor sit amet
output: 1
output: consectetur adipiscing elit
output: 0

How do I wrap the echo statements in a conditional, so only when ['options'][4] == '1' it will run?

if ($array[$i]['options'][4] == '1') {
...
}

Doesn't work and returns nothing, set it to == '0' and you'll get everything. I've tried assigning it to a variable first, tried converting to ints first, but they all seem to return 0, while an echo displays the value.

Got night-time creative with foreach loops, trying to drill down to the items, only resulting in loss of keys where values were still properly read. Its probably something simple, but its been ages since I dabbled with php and arrays.

Answer 1

Wrap it with a simple if. But why use txt? shouldn't you use options?

if(isset($array[$i]['options'][4]) and $array[$i]['options'][4]==1){
  echo 'output: '.$array[$i]['options'][0]."<br />";
  echo 'output: '.$array[$i]['options'][4]."<br />";
}