doubiankang2845 2012-06-03 22:25
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从另一个表中选择服务器名称

I have two tables, files and servers. Here's the schema:

f_id, s_id, u_id, name, size, downloads, uploaded

s_id, name, description, disk_space, used_space, enabled

Now, I'm trying to get some information about a particular file as well as what server it's hosted on. In the files table, this is determined by the s_id column, which is a foreign key to the servers table. I want to retrieve the files name, size, time it was uploaded and what server it's on. I tried this:

public function get_file_details()
{
    $sql= 'SELECT name, size, uploaded, server
           FROM `files` f
           JOIN `servers` s
           ON f.s_id = s.u_id
           WHERE f_id = ?
           LIMIT 1';
}

but it doesn't work. What am I doing wrong?

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2条回答 默认 最新

  • dongshuming7131 2012-06-03 22:33
    关注
    public function get_file_details()
    {
        $sql= 'SELECT f.name, size, uploaded, s.name
               FROM `files` f
               JOIN `servers` s
               ON f.s_id = s.s_id
               WHERE f_id = ?
               LIMIT 1';
    }
    

    3 changes: name => f.name, server => s.name, ON f.s_id = s.u_id => ON f.s_id = s.s_id

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