dongyi9330 2011-05-16 00:17 采纳率: 100%
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查询计数和功能无法正常工作

I am using the code below to select items and using the $result variable to do a count. if there are less than 1 it will say add more and if there are more than 5 it will say view all. It works for less than 1 but it won't for more than 5. Am i doing it right?

//Query

$sql = "SELECT id, name, why, date_time 
          FROM tabs 
         WHERE p_id = '$pid'
      ORDER BY id 
         LIMIT 0, 5";

$result = mysql_query($sql);
$query = mysql_query($sql) or die ("Error: ".mysql_error());

if ($result == "") {
  echo "";
}

echo "";

$rows = mysql_num_rows($result);

if($rows == 0) {
  print("");
} elseif($rows > 0) {
  while($row = mysql_fetch_array($query)) {
    $name = $row['name'];
    $w = nl2br($row['why']);
    $y = $row['date_time'];

    print("echoing contents here");
  }
}

if(mysql_num_rows($result) > 5) {
  echo "view all";
}

if(mysql_num_rows($result) < 1) {
  echo "add one";
} ?>
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1条回答 默认 最新

  • douyan9417 2011-05-16 00:23
    关注
     if(mysql_num_rows($result) > 5) {
      echo "view all";
      }
    
     if(mysql_num_rows($result) < 1) {
       echo "add one";
      } 
    

    Should be

     if($rows > 5) {
      echo "view all";
      }
    
     if($rows < 1) {
       echo "add one";
      }
    

    Since you exhausted the result set with the previous mysql_fetch_array() loop

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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