使用正则表达式获取所有图像和除图像之外的所有图像

Question

I have an article with text and multiple images in it and need to get just images and just text, separately.

Now I have this code and it just returns last image in article:

preg_match('/<img.+src=[\'"](?P<src>.+?)[\'"].*>/i', $article, $img);

How to select all images and do reverse for getting just text?

Thank you

Answer 1

You can use the DOM for that:

$imgSrc = array();
$txt = '';

$dom = new DOMDocument();
@$dom->loadHTML($article);

$imgs = $dom->getElementsByTagName('img');

foreach ($imgs as $img) {
    $imgSrc[] = $img->getAttribute('src');
}

$xpath = new DOMXPath($dom);
$textNodes = $xpath->query('//*[not(self::script) and not(self::style)]/text()');
foreach ($textNodes as $textNode) {
    $tmp = trim($textNode->textContent);
    $txt .= (empty($tmp)) ? '' : $tmp . PHP_EOL;

}

XPath query details:

// means anywhere in the DOM tree
* means all tag nodes
[.....] defines a condition
not(self::script) : the current node must not be a script node
text() returns the text node