如何使用PHP或正则表达式提取图像名称？

Question

I have the following data in MySQL.

<p><img src="../../../../assets/images/frontpage/image1.png" 
alt="" width="790" height="356" /></p>

Now I want to get image2.png with PHP or regex. The extension can be gif or jpg. And a length of image name can be any length.

Answer 1

This would match a path in an img tag and capture the file in the first interior capturing group.

<?php
if (preg_match('%<img\s.*?src=".*?/?([^/]+?(\.gif|\.png|\.jpg))"%s', $subject, $regs)) {
    $image = $regs[1];
} else {
    $image = "";
}
?>