如何在Javascript中使用PHP中的JSON数据（数组）

Question

I would like to retrieve each element inside of this.responseText, and put them in my HTML on Javascript. Is there something wrong in my code? I hope my code helps you to understand my question. Thanks. (p.s. the html code is provided, and so I cannot use jquery.)

an example of this.responseText is below; (By using alert, I got that)

{"name":"Hermione Grainger","number":"4","review":"Not as good as the NEXT book in the series, but hilarious and satisfying."}{"name":"Ronald Drumpf","number":"1","review":"Feminist propaganda!"}{"name":"Brienne of Tarth","number":"5","review":"Alanna is my best friend."}

And my java script is below;

function bookReview(){
    var reviews = JSON.parse(this.responseText);
    for(var i=0; i<reviews.length; i++){
        var name = document.createElement("h3");
        var text = document.createElement("p");
        name.innerHTML = reviews[i].name + reviews[i].number;
        text.innerHTML = reviews[i].review;

        document.getElementById("reviews").appendChild(name);
        document.getElementById("reviews").appendChild(text);
    }
}

or is there something wrong in my PHP code??

$path = "books/$book/";
review(glob($path . "review" . "*" . ".txt"));

function review($reviews) {
    foreach ($reviews as $each) {
        $review = file($each, FILE_IGNORE_NEW_LINES);
        $output = array (
            "name" => $review[0],
            "number" => $review[1],
            "review" => $review[2]
            );
        header("Content-type: application/json");
        print(json_encode($output));
    }
}

Answer 1

This doesnt look like valid JSON, should be like '[{},{},{}]'. If you want you can use a JSON validator, e.g. http://json-validator.com/.

To generate the JSON array properly you can do:

$array = [];
foreach ($reviews as $each) {
    $review = file($each, FILE_IGNORE_NEW_LINES);
    $output = array (
        "name" => $review[0],
        "number" => $review[1],
        "review" => $review[2]
        );
    array_push($array,$review);
}
print(json_encode($array));