doulou0882 2016-06-25 16:26
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Symfony 3 - 必须是FormFactoryInterface的一个实例,给出FormFactory的实例

I want to get my form out of a Service, but whatever I do, it just won't work.

I have the service in the YML

services:      
  myservice:
     class: AppBundle\Service\Myservice
     arguments: ["@doctrine.orm.entity_manager","@form.factory"]

then in AppBudle\Service\Myserivce.php:

namespace AppBundle\Service;

use Doctrine\ORM\EntityManager;

use Symfony\Component\Form\FormBuilderInterface;

use Symfony\Component\Form\Extension\Core\Type\TextType;

class Myservice {

protected $em;
protected $formFactory; 

public function __construct(EntityManager $entityManager, FormFactoryInterface $formFactory) {
    $this->em = $entityManager;
    $this->formFactory = $formFactory;
    }   


// GENERATE CALCULATOR FORM
public function generateCalculatorForm() {  


     return  'ffffsdsd';
    }

}

But I get a

Catchable Fatal Error: Argument 2 passed to AppBundle\Service\Myservice::__construct() must be an instance of AppBundle\Service\FormFactoryInterface, instance of Symfony\Component\Form\FormFactory given, called in D:\xamp\htdocs\icp\var\cache\dev\appDevDebugProjectContainer.php on line 409 and defined

What is wrong here? I already tried almost everything i found on the web, but cant get this working.

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1条回答 默认 最新

  • dongyi8416 2016-06-25 18:28
    关注

    http://php.net/manual/en/language.namespaces.php

    Class/interface name is prepended by current namespace name if its name is not full.

    Set full name for FormFactoryInterface or add it in use statements

    use Symfony\Component\Form\FormBuilderInterface;
    use Symfony\Component\Form\Extension\Core\Type\TextType;
    use Symfony\Component\Form\FormFactoryInterface;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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