如何使用Guzzle6发出此POST请求

Question

My working Guzzle5 code looks roughly as follows:

$guzzle = new \GuzzleHttp\Client();
$request = $guzzle->createRequest('POST', $url);
$request->setHeader('Authorization', 'Bearer ' . $token);
$postBody = $request->getBody();
$postBody->setField('name', 'content');//several times
if (check for file) {
    $postBody->addFile(new \GuzzleHttp\Post\PostFile('name', fopen(...));
}
$response = $guzzle->send($request);

What with setting a header and maybe adding a file, I’m not sure how to do this with Guzzle6.

Answer 1

Here an example from the official documentation how can you set headers and adding file into your POST request with Guzzle 6:

$client = new \GuzzleHttp\Client();
$client->post('/post', [
    'multipart' => [
        [
            'name'     => 'foo',
            'contents' => 'data',
            'headers'  => ['X-Baz' => 'bar']
        ],
        [
            'name'     => 'baz',
            'contents' => fopen('/path/to/file', 'r')
        ],
        [
            'name'     => 'qux',
            'contents' => fopen('/path/to/file', 'r'),
            'filename' => 'custom_filename.txt'
        ],
    ]
]);

The multipart option sets the body of the request to a multipart/form-data form, if you don't need to work with files you can just use form_params instead of multipart option.

Any headers you can easy set with help headers option.

Additional info you can find here Guzzle Upgrade Guide (5.0 to 6.0)