I'm trying to use the PHP passthru function to execute an OS command on Linux.
I am using it as follows. The Linux command is just to list files in a directory I know does not exist and then I am just echoing the status to make sure it's not 0.
$osexec = "ls /tp";
$status = 0;
$result = passthru($osexec, $status);
echo $status;
However the status seems to be the entire output of the command including the status number
ls: /tp: No such file or directory
2
Why is this?
我正在尝试使用PHP passthru函数在Linux上执行OS命令。
我使用它如下。 Linux命令只是列出我知道不存在的目录中的文件然后我只是回显状态以确保它不是0。
$ osexec =“ls / tp“;
$ status = 0;
$ result = passthru（$ osexec，$ status）;
echo $ status;
但是状态似乎是命令的整个输出，包括状态编号
ls：/ tp：没有这样的文件或目录
2
< / pre>
为什么会这样？
You are seeing stderr plus the $status value. To hide stderr you could do the following:
微信扫一扫// 2> /dev/null to hide stderr
$osexec = "ls /tp 2> /dev/null";
$status = 0;
$result = passthru($osexec, $status);
echo $status;