doutenglou6588 2019-06-18 14:34 采纳率: 0%
浏览 230
已采纳

在php passthru中使用变量

I would like to put my variables inside my passthru,

$cut1 =DNAseq1 
$cut2 = DNAseq2

I have already checked this topic but didn't find how to proceed

echo passthru('sudo docker run my_docker bash -c "-check "' .$cut1.'"  "'.$cut2);

but nothing is displayed on the screen but when I wrote directly the DNAseq1:

echo passthru('sudo docker run my_docker bash -c "-check ATCG "'.$cut );

It works....but only when I wrote one variable not for 2
So what is the problem ??

  • 写回答

1条回答 默认 最新

  • doukuangxun5382 2019-06-20 15:17
    关注

    Try this:

    echo passthru("sudo docker run my_docker bash -c '/home/prg/soap -check $cut1 $cut2'");
    

    I've used double quotes around the argument to passthru() so I can substitute variables more clearly.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 java 的protected权限 ,问题在注释里
  • ¥15 这个是哪里有问题啊?