dso407787736 2016-10-30 03:07
浏览 41
已采纳

不能用变量过滤雄辩的集合

I can't filter a collection with a variable:

    $sections = Section::all();
    $courses = array("MATH282", "MATH201" , "GEOM202");
    foreach ($courses as $course)
    {
        $sections1 = $sections->filter(function($foo)
        {
            if ($foo->course == $course ) {
            return true;
            }
        });
    }

The filter works if the condition is a string. Everything else works.

  • 写回答

1条回答 默认 最新

  • dongweicha6077 2016-10-30 03:21
    关注

    You are missing use() function in filter closure function. Your code should be as:

     $sections = Section::all(); $courses = array("MATH282", "MATH201" , "GEOM202");
     foreach ($courses as $course) { 
        $sections1 = $sections->filter(function($foo) use($course)  { 
           if ($foo->course == $course ) { 
                return true; 
           }
        });
     }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 phython如何实现以下功能?查找同一用户名的消费金额合并—
  • ¥15 孟德尔随机化怎样画共定位分析图
  • ¥18 模拟电路问题解答有偿速度
  • ¥15 CST仿真别人的模型结果仿真结果S参数完全不对
  • ¥15 误删注册表文件致win10无法开启
  • ¥15 请问在阿里云服务器中怎么利用数据库制作网站
  • ¥60 ESP32怎么烧录自启动程序
  • ¥50 html2canvas超出滚动条不显示
  • ¥15 java业务性能问题求解(sql,业务设计相关)
  • ¥15 52810 尾椎c三个a 写蓝牙地址