什么做的 在方法参数中做什么？ [重复]

Question

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• Reference — What does this symbol mean in PHP? 18 answers

I have been reading PHP conventions in OOP and come across the | operator/symbol which I cannot find any information on. After trial and error testing in an enviroment, I found that if the parameter is not a data-type int then the variable to the right of the parameter is outputted.

For example, let's use a class like this:

class MyClass {
    const FROM_DB = 1;
    const PUBLIC_ONLY = 0;

    public static function getSomething($input, $db = 0, $public = 1) {
        return $input;
    }
}

This use-case would return 1:

echo MyClass::getSomething( 'test' | MyClass::FROM_DB | MyClass::PUBLIC_ONLY );

This use-case would return 7:

echo MyClass::getSomething( 6 | MyClass::FROM_DB | MyClass::PUBLIC_ONLY );

Finally, this use-case would return 'test':

echo MyClass::getSomething( 'test' , MyClass::FROM_DB | MyClass::PUBLIC_ONLY );

I do not understand what the | is doing in this? I found it here. Can anyone explain what this is called and how it is used correctly?

Thank's in advance, see it working here.

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Answer 1

It's a bitwise OR operator.

bitwise operations wikipedia