dsl2014 2016-05-13 10:00
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根据MySQL表行中的值生成HREF链接

I have the following PHP, my question is; how can I make the href generate itself based on the value of $row['category']? If anything is unclear, please let me know.

<?php
    echo "<div class=News>";
$q = "SELECT * FROM post ORDER BY newsno DESC";
$r = mysqli_query($mysqli, "$q");
if($r)
{

while($row=mysqli_fetch_array($r)){
    echo "<form action=index.php method=post>";
    echo "<div class=Container>";
    echo "<div class=Newsheader>";
    echo "<h7>";
    echo $row['newstopic'];
    echo "</h7>";
    echo "</div>";
    echo "<a href=image.php?newsno=".$row['newsno']." data-lightbox=roadtrip><img src=image.php?newsno=".$row['newsno']." width=180 height=180/></a>";
    echo "<div class=tb>";
    echo nl2br(substr ($row['newsinfo'], 0, 50));
    echo "<a href='This/Is/My/problem"."'> ...Read more</a>";
    echo "</div>";
    echo "</div>";
    echo "<div class=newsfooter>";
    echo 'Category: ' . $row['category']; 
    echo "</div>";
    echo "</br>";
    echo "</br>";
    echo "</form>";
}
echo "</div>";

}

else
{
echo mysqli_error();
}

?>
  • 写回答

1条回答 默认 最新

  • douzhui1972 2016-05-13 10:13
    关注

    if you are trying to make dynamic url according to category than you need to put

    echo '<a href="https://www.vg.no/'.$row['category'].'"> ...Read more</a>';
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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