doob0526 2016-03-08 21:56
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虽然循环没有显示所有结果php,但它消除了一个结果

Every time i use this code it eliminates one result.

Lets say if i have 10 rows from the database, it will only display 9 rows

I am aware this code is not in PDO or MySQLI, but that isn,t the issue

mysql_select_db($database_localhost, $localhost);
$query_tutorunit = "SELECT * FROM tutorunit WHERE tutorID = $colname_unitg";
$tutorunit = mysql_query($query_tutorunit, $localhost) or die(mysql_error());
$row_tutorunit = mysql_fetch_assoc($tutorunit);
$totalRows_tutorunit = mysql_num_rows($tutorunit);


$confirmtwo = "";
while ($row_tutorunit = mysql_fetch_array($tutorunit)) {
    $confirmtwo .= $row_tutorunit["code"];
}
echo $confirmtwo;

When i use do while it shows all the results.

<?php do { ?>
<p><?php echo $row_tutorunit["code"]; ?></p>
<?php } while ($row_tutorunit = mysql_fetch_assoc($tutorunit)); ?>

But i do not want to use do-while Where am i going wrong?

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1条回答 默认 最新

  • douweng3383 2016-03-09 00:04
    关注

    Remove that line:

    $row_tutorunit = mysql_fetch_assoc($tutorunit);
    

    Both mysql_fetch_assoc and mysql_fetch_array move the pointer.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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