doucai1901 2015-11-08 23:22
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如何填充包含的树枝模板中的变量

I want to be able to populate up variables from included twig templates, just like when you're extending another template. Here's an example:

I have base.twig as follows:

{# base.twig #}
<html>
    <head></head>
    <body class="body {{class_from_index}}">
        <nav>...</nav>
        {% block content %}
        {% endblock %}
        <footer>...</footer>
    </body>
</html>

and index.twig as follows:

{# index.twig #}
{% extends "base.twig" %}

{% set class_from_index = 'index' }

{% block content %}
    <div>My actual content</div>
{% endblock %}

doing like this, the variable class_from_index is populated to base.twig, when I'm rendering index.twig. However if i have gallery.twig like this:

{# gallery.twig #}
{% set class_from_index = 'gallery' %}
<div>
    A gallery
</div>

and adding {% include gallery.twig %} in index.twig, the variable class_from_index is not populated up to index.twig or base.twig. I know that if gallery.twig extends index.twig and index.twig extends base.twig, this will work, but this is not the case.

Is there a way to achieve what I'm trying to explain? Thank you :)

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1条回答 默认 最新

  • douaoj0994 2015-11-09 08:14
    关注

    The problem

    If <kbd>main.twig</kbd> contains:

    {% include "gallery.twig" %}

    The compiled result will be:

    protected function doDisplay(array $context, array $blocks = array())
{
    // line 1
    $this->loadTemplate("gallery.twig", "main.twig", 1)->display($context);
}

    And if <kbd>gallery.twig</kbd> contains:

    {% set var = 42 %}

    The result is:

    protected function doDisplay(array $context, array $blocks = array())
{
    // line 1
    $context["var"] = 42;
}

    As you can see, the context is not given as a reference, so your variable can't be populated.

    The PHP equivalent

    The reason is quite obvious. It looks very exotic to use variables from a lower scope to a upper one. That's like if you were doing in PHP:

    <?php

function gallery() {
  $var = 42;
}
gallery();

echo $var;

    There must be a better solution to your problem... by designing your templates architecture another way. The question itself is not relevant, that's totally out of good practices.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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