douluan4644 2014-10-13 22:58
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日期存储到数据库时会出错

I have two datepickers in format dd/mm/YYYY. Problem is that when I store them to database, they got buggy. Output is "1970-01-01'. I am also using mySQL STR_TO_DATE function and php built in function for date format... I don't know why my dates are not working. Can someone told me why my dates got buggy?

Here is code that I am using:

$datumDO=$_POST['datepicker'];
$datumOD=$_POST['datepicker1'];
$time = strtotime($datumDO);
$NewDatum = date('d/m/Y',$time);    
$time = strtotime($datumOD);
$NewDatumOD = date('d/m/Y',$time);
    if ($stmt = $dbConnection->prepare("INSERT INTO `cat-item` (id_cat, id_item, datumOD, datumDO) VALUES (?,?,STR_TO_DATE(?,'%d/%m/%Y'),STR_TO_DATE(?,'%d/%m/%Y'))")){
        $stmt->bind_param('iiss', $category, $item, $NewDatum , $NewDatumOD;
        $stmt->execute();
        $stmt->close();
}
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2条回答 默认 最新

  • dstnlhhv791576 2014-10-13 23:59
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    $datumDO= date('Y-m-d', strtotime($_POST['datepicker']));
    $datumOD= date('Y-m-d', strtotime($_POST['datepicker1']));
        if ($stmt = $dbConnection->prepare("INSERT INTO `cat-item` (id_cat, id_item, datumOD, datumDO) VALUES (?,?,?,?)")){
            $stmt->bind_param('iiss', $category, $item, $datumDO, $datumOD;
            $stmt->execute();
            $stmt->close();
    }
    

    try this.....hope this helps

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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