从sql查询中检索特定数据

Question

Let's say I have the following query, wich gives me the amount of coupons downloaded and redeemed, grouped by date: [EDIT](I can't modify this query)[/EDIT]

$sql = "SELECT DATE(datetime) ,
                           SUM(CASE WHEN datetime!=''  THEN 1 ELSE 0 END) As downloaded ,
                           SUM(CASE WHEN used = 1 AND DATE(datetime) != '' THEN 1 ELSE 0 END) AS redeemed

                     FROM Promotion_Redeem
                     WHERE datetime BETWEEN '2013-10-01' AND '2013-10-04'
                     GROUP BY DATE(datetime)";

How can I get the sum of downloaded and the sum of redeemed? this should be within $sql, somewhere... below is the result for this query:

row number 1
array (size=3)
0 => string '2013-10-01' (length=10)
1 => string '126' (length=3)
2 => string '11' (length=2)
row number 2
array (size=3)
0 => string '2013-10-02' (length=10)
1 => string '106' (length=3)
2 => string '5' (length=1)
row number 3
array (size=3)
0 => string '2013-10-03' (length=10)
1 => string '228' (length=3)
2 => string '12' (length=2)
row number 4
array (size=3)
0 => string '2013-10-04' (length=10)
1 => string '149' (length=3)
2 => string '9' (length=1)

[EDIT]bove you can see I get 4 rows, each one whith an array... I want, for instance, the sum of the third field from each of these arrays... In my example, this would equals to 37 (that means, 37 coupons redeemed)[/EDIT] I got this data structure after using this:

while ($row = mysql_fetch_row($result)) {
            echo "row number ".++$i;
            var_dump($row);

        }

Thanks in advance

Answer 1

Modify your php loop like so:

$downloaded=0;
$redeemed=0;
while ($row = mysql_fetch_row($result)) {
        echo "row number ".++$i;
        $downloaded+=$row[1];
        $redeemed+=$row[2];
        var_dump($row);
    }
echo "Downloaded: $downloaded<br>";    
echo "Redeemed: $redeemed<br>";