从java程序执行php

Question

Here is my code:

String cmd = "bash -c \"php /Users/phyrrus9/Projects/java-web/test.php | say\"";
System.out.println("Executing: " + cmd);
Runtime rt = Runtime.getRuntime();
Process pr = rt.exec(cmd);

Yet, it is never executed. I can run that command from a shell and it works fine. Here is the contents of test.php

<?php
     echo hello;
?>

Answer 1

Runtime.exec() is not a shell or a command interpreter, and is not treating your command the way you think it is. The single-String argument version of exec() does a simple brain-dead split on spaces, so your quotes and escaped quotes are meaningless; they are never making it to bash in the way you think.

Always always use one of the execs that take a String[] cmdarray

Your args in this case are

"bash"
"-c"
"\"php /Users/phyrrus9/Projects/java-web/test.php | say\""

That is, you are running bash -- the first arg you are giving it is -c and the second arg is the string.

Also see this answer to the more general question of how to Execute external program from Java.