duanlv5084 2013-04-17 17:58
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使用PHP进行参数化更新SQL查询

I have a table where two entries has id = 10. My SQL update query looks like this:

$q = "UPDATE `table_name` SET `col_name` = 'value' WHERE `id` = ?";
if($con-prepare($q)){
    $stmt->bind_param("i","10");
    $stmt->execute;
    $stmt->fetch;
    $stmt->close();
}

The query will not run, where is the error in it? And also, when it does run, will it update ALL entries where id = 10 or just the first one?

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  • dsy1971 2013-04-17 18:01
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    $stmt->execute();
    $stmt->fetch();
    

    Do not forget the () to show that's a method call else PHP interprets it as a property access.

    And write: $stmt = $con->prepare() instead of $con-prepare() (or do you want to subtract the return of the function call to prepare() from $con?)

    It'll update all the entries with id=10

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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