duanlang0025 2014-08-12 04:29
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如何在字符串中搜索带有变量的子字符串，并将其替换为包含带有PHP的子字符串变量的内容？

Lets suppose I have a string:

$text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!"

I want to replace each occurrence of "exec?" in the string with some new text and at the same time I want to store the text that follows "exec" in a separate variable so it can be used when replacing the text.

For example, say I want to replace each occurrence of exec??? with, < html>???< /html>< div>???< /div> , so that the resulting string is:

$text2 = "This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!"

How can I do this in PHP?

Thanks very much in advance.

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  • drdyf42880 2014-08-12 07:18
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    Here is a way to go using preg_replace:

    $text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!";
$text2 = preg_replace('/\bexec(\S+)/', "<html>$1</html><div>$1</div>", $text);
echo $text2,"
";

    This will replace all occurrences of execwhatever.
    \S+ stands for any NON space character.
    \b is a word boundary.

    You may find more info here.

    Output:

    This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!

    Update according to comment

    If you want to replace more than one string, just do:

    $text2 = preg_replace('/\bexec([^:\s]+):([^:\s]+)/', "<html>$1</html><div>$2</div>", $text);

    Where [^:\s] means any character that is not semi-colon or space

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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