dongxi3209 2014-04-16 16:52
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使用指定的自定义范围进行舍入

i need a function that can round from a defined custom range...

for example:

0.01 - 0.39 = round to 0
0.40 - 0.74 = round to 0.5
0.75 - 0.99 = round to 1

if number is 2.33 it should show as 2.0
if number is 2.67 it should show as 2.5
if number is 2.89 it should show as 3.0

i tried something but doesn't work at all...

code:

$range1 = range(0.01, 0.39, 0.01);
$range2 = range(0.40, 0.74, 0.01);
$range3 = range(0.75, 0.99, 0.01);

function round_range($num) {
    global $range1, $range2, $range3;

    if (in_array($num, $range1))
        return round($num, 0, PHP_ROUND_HALF_DOWN);
    else if (in_array($num, $range2))
        return round($num, 0, PHP_ROUND_HALF_DOWN);
    else if (in_array($num, $range3))
        return round($num, 0, PHP_ROUND_HALF_DOWN);
    else
        return "error";
}

echo round_range(0.35);
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2条回答 默认 最新

  • douqiao6563 2014-04-16 17:09
    关注

    Sounds like you should just write your own code for this function...

    public function roundWithDefinedRange($num) {
        $rangeDefinitions = array (
            array ( array ( 0.01, 0.39 ) , 0 ),
            array ( array ( 0.40, 0.74 ) , 0.5 ),
            array ( array ( 0.75, 0.99 ) , 1 ),
        );
    
        $decimal = $num - floor($num);
    
        foreach ($rangeDefinitions as $range) {
            if ($decimal >= $range[0][0] && $decimal <= $range[0][1]) {
                return floor($num)+$range[1];
            }
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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