从变量和数组创建选择菜单[关闭]

Question

I am trying to figure out how I can create a select menu that has the variable '$portfolios' number of options, but only show the option if the array $portfolio_list has less than 3 in the array segment that corresponds to the option.

So for example. There are 2 portfolios, with 2 assigned to the first, and 1 assigned to the second. So I need two options created in my select, both available.

$portfolios = '2';

$portfolios_list = array(2,1);

If the first option has 3 assigned as below, I would only want the second to appear as an option.

$portfolios = '2';

$portfolios_list = array(3,1);

I also need the option to carry the correct number. So 1, or 2. If 1 is hidden, the only option would show 2.

Any help would be great.

Answer 1

you can access parts of the array like so

$portfolios_list[0]; //in your second example this would equal 3
$portfolios_list[1]; //in your second example this would equal 1

So do something like

if($portfolios_list[0] != '3'){
YOUR CODE
}

that just says if it is not 3 execute YOUR CODE