如果变量不包含值，则不显示变量（PHP |

Question

I am using SOAP to get some data from other service, i get XML and convert and display it with PHP. The thing is sometimes there is no value for it in XML file and i dont know how to display some message like "This thing was not set", instead of that i am just getting notice with Notice: Array to string conversion in \data2.php on line 636 Array

What i tried:

                  if(isset($claim ['vehicle']['engine-cc']))
                  echo  var_dump($claim ['vehicle']['engine-cc']);

output: array(0) { }

After that i try something like:

                  if(isset($claim ['vehicle']['engine-cc']))
                  echo  var_dump(isset($claim ['vehicle']['engine-cc']));

Output: bool(true)

So it looks i am doing things bad, can you gimme some advise how can i fix it?

p.s. I know i can stop displaying errors and notices but its not the way how i want to "fix" it

Answer 1

you no need to echo after var_dump already have var_dump(used for printing array) or may be you have not an array for $claim ['vehicle']['engine-cc'] it's a string

 var_dump($claim ['vehicle']['engine-cc']); // for array
 echo $claim ['vehicle']['engine-cc'] // for string

returning bool(true) cause you have isset()(will return boolean true/false)

var_dump(isset($claim ['vehicle']['engine-cc']));

For printing array values you only need :-

var_dump($claim ['vehicle']['engine-cc']); or var_dump($claim);

will return you complete array output

for any check empty values try

if(!empty($claim ['vehicle']['engine-cc']))
  var_dump($claim ['vehicle']['engine-cc']);