dongqiang8058 2014-01-17 04:20 采纳率: 100%
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如何将变量附加到php中的对象

I have this, that doesnt work obviously.

$start = $hours->start{$day};

I need to be able the change the $day dynamically. $day can be any day of the week

//For example
$start = $hours->startSunday;

Let me try to be more clear. The following objects contain a certain time

// will echo something like 8:00am
echo $hours->startSunday;

//will echo something like 7:00am
echo $hours->startMonday;

I need to be able to change the day part dynamically with a variable, since it can be any day of the week.

//so something like
echo $hours->start.$day;

but that doesnt work

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2条回答 默认 最新

  • doupu0619 2014-01-17 04:42
    关注

    First. You could edit syntax with

    $hours = new stdClass();
    $day = 'Sunday';
    $hours->{'start'.$day} = 10;
    $start = $hours->{'start'.$day};
    var_dump($start);
    

    Secnod. Better ot use getter and setter methods.

    class Hours
        {
        private $hours = array();
        public function getStart($day)
            {
            return $this->hours[$day];
            }
        public function setStart($day, $value)
            {
            $this->hours[$day] = $value;
            }
        }
    $hours = new Hours();
    $day = 'Sunday';
    $hours->setStart($day, 10);
    $start = $hours->getStart($day);
    var_dump($start);
    
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