douqiang4245 2013-09-23 23:14
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在php中转换日期会根据日期格式返回不同的结果

What seemed to be a fairly standard date conversion is giving me unusual results. I want to get $pay_date into the 'j/d/Y' format, but can only get the correct date if the format is 'Y-m-d'.

Here's my code:

$payment = '2014-09-09';
$pay_date = strtotime("+1 month", strtotime($payment) );                    
$converter = date('j/d/Y', $pay_date );

echo $converter;

result: 9/09/2014 (should be 10/09/2014)

If I keep these variables, but change $converter to this format:

$converter = date('Y-m-d', $pay_date );

the result is correct - 2014-10-09

I also tried this:

$convert2 = DateTime::createFromFormat('Y-m-d', $pay_date)->format('j/d/Y');
echo $convert2;

result: 9/09/2014

but:

$convert2 = DateTime::createFromFormat('Y-m-d', $pay_date)->format('Y-m-d');
echo $convert2;

gives me the correct result: 2014-10-09

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1条回答 默认 最新

  • doukeng7426 2013-09-23 23:19
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    j and d are the same formatting options, they both represent DAYs; from the manual for PHP's date function:

    d  Day of the month, 2 digits with leading zeros  01 to 31
    j  Day of the month without leading zeros         1 to 31
    

    Use the format 'm/d/Y'.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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