doujia4041 2013-07-07 12:15
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来自重写URL的Ajax调用

I'm trying to make an ajax call from within a page with a rewritten URL.

request = $.ajax({
                url: "myajaxcode.php",
                type: "post",
                data: formData
            });

The resulting request is .../Folder/Rewritten_Name/myajaxcode.php

For this to work the url should be .../Folder/myajaxcode.php

I also tried using a backslash in the url: "/myajaxcode.php", this resolves to /myajaxcode.php

The ajax works when I provide the absolute URL or if I use a function that calculates and base URL and prefixes it the php file name. However, ideally I wanted to avoid using absolute urls or additional functions.

Is there a better way of handling the ajax call?

My htaccess is

RewriteEngine on
RewriteBase /Folder/
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d

RewriteRule ^Rewritten_Name/([^/]+) Rewritten_Name.php?r=$1
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1条回答 默认 最新

  • drpiqlzrh62917192 2013-07-07 12:38
    关注

    If you are making a request from example.com/Folder/foo.php to example.com/Folder/myajaxcode.php you can use relative URl, like this:

    request = $.ajax({
                url: "./myajaxcode.php",
                type: "post",
                data: formData
            });

    Assuming that rewrite rules defined are correct, working exactly you want them to be & base url meta tag is set correctly in html.

    further another approch, I have been people taking is: setting a global js variable from PHP in some function & the call the function in <head> where ever they want to ajax. like this

    <?php
 function set_ajax_url($script_path){
   $ajax =  "<script type='text/javascript'>";
   $ajax .= "window.MY_AJAX_URL = ";
   $ajax .= $_SERVER['HTTP_HOST'] . $script_path;
   $ajax .= "</script>";
   echo $ajax;
 }

    add this in your template/layout

    <html>
<head>
 <?php set_ajax_url('Folder/myajaxcode.php'); ?>
</head>

    you use can this like this:

    request = $.ajax({
                url: MY_AJAX_URL,
                type: "post",
                data: formData
            });

    so, you will have to change the url at one place :)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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