闭包有可能知道哪个函数是一个参数？

Question

In the code below, is there a single way for $bar() to know that it was called being an argument of foo():

// This function belongs to a 3er party library I don't have access to 
function foo( $baz ){
    // code here
}

// This is my function
$bar = function(){
    $argumentOf = ???;  // some dark magic here
    echo $argumentOf;   // print "foo"
    // more code goes here
    return "something interesting";
};

echo foo( $bar() );

I know that I could make $bar() to accept an argument and then call it like this:

foo( $bar( "foo" ) );

It is possible without explicitly passing the name of the function?

I tried debug_backtrace to no avail.