douqingzhi0980 2019-06-23 18:48
浏览 67

laravel中的Sql查询

i have two tables, products table and its photos table. I want to query products with one of their photo. my below sql query give me the result but in laravel i don't know how to use functions to take same result.

  select products.*, pphotos.name as pname from products 
         INNER JOIN pphotos on products.id = pphotos.product_id
         GROUP BY products.id
  • 写回答

1条回答 默认 最新

  • dqdjfb2325 2019-06-23 18:55
    关注

    You need to make use of the query builder https://laravel.com/docs/5.8/queries

    $products = DB::table('products')
        ->select('products.*', 'pphotos.name as pname')
        ->join('pphotos', 'products.id', '=', 'pphotos.product_id')
        ->groupBy('products.id')
        ->get();
    

    Edit

    To work around the issue where an item in your select list is not functionally dependent, you can modify the query like so:

    $products = DB::table('products')
        ->selectRaw('products.*, ANY_VALUE(pphotos.name) as pname')
        ->join('pphotos', 'products.id', '=', 'pphotos.product_id')
        ->groupBy('products.id')
        ->get();
    

    or you can simply disable strict mode in your config/db.php

    'mysql' => [
        ...
        'strict' => false,
    ]
    

    Disclaimer

    However, note that if the pphotos.name within the same group differ in value, it will be unpredictable which pphotos.name mysql will return as a result.

    评论

报告相同问题?

悬赏问题

  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 unity第一人称射击小游戏,有demo,在原脚本的基础上进行修改以达到要求
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?
  • ¥15 加热介质是液体,换热器壳侧导热系数和总的导热系数怎么算
  • ¥100 嵌入式系统基于PIC16F882和热敏电阻的数字温度计
  • ¥15 cmd cl 0x000007b
  • ¥20 BAPI_PR_CHANGE how to add account assignment information for service line
  • ¥500 火焰左右视图、视差(基于双目相机)