内部函数调用的结束函数 - PHP

Question

I have a function which needs multiple checks and for that, I have added multiple functions but when some inner-function fails it needs to return the response as failed but it does not and continues the next inner-function

 public static function doMultipleWorks(){

  self::checkFirstCondition();
  self::checkSecondCondition();

  ...
  ...

  return response(['status' => true, 'data' => [...]]);

 }

 public static function checkFirstCondition(){

  ....
  ....
  if(this != that){
    return response(['status' => false, 'error_msg' => 'this is not equal to that']]
  }

 }

 public static function checkSecondCondition(){

  ....
  ....
  if(this != that){
    return response(['status' => false, 'error_msg' => 'this is not equal to that']]
  }


 }

The problem is that if the first or second function fails it still continues and it does not break out of the function. Any help would be highly appreciated.

Answer 1

You need to check the response of functions and on response bases, you should continue or break further processes. I believe you should do something like this:

public static function doMultipleWorks(){

  $firstResponse = self::checkFirstCondition();
  if ($firstResponse['status'] == false) {
       return $firstResponse;
  }
  $secondResponse = self::checkSecondCondition();
  if ($secondResponse['status'] == false) {
       return $secondResponse;
  }

  ...
  ...

  return response(['status' => true, 'data' => [...]]);

 }

 public static function checkFirstCondition(){

  ....
  ....
  if(this != that){
    return response(['status' => false, 'error_msg' => 'this is not equal to that']]
  }

 }

 public static function checkSecondCondition(){

  ....
  ....
  if(this != that){
    return response(['status' => false, 'error_msg' => 'this is not equal to that']]
  }


 }

Hope it helps you to fix your approach.