检查laravel中的至少表单数据是否为空

Question

I am building a search function in laravel 5.6 I have multiple form fields. And everything is fine with search queries. And with out empty form data it returns all datas from db. I want to check if atleast a field is not empty to pass queries else i want to return error. How can i do that in Laravel. Thanks in advance

if ($request->all() != '') {
            // Search for  nursery based on their freeword.
            if (!empty($request->input('description'))) {
                $nursery->Where('description',  'LIKE', '%' . $request->input('description') . '%');
                $nursery->orWhere('name',  'LIKE', '%' . $request->input('description') . '%');
} 

Answer 1

this will validate your required inputs and gives error if any missing , else it will search

use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Validator;

public function search(Request $request){
        $validator = Validator::make($request->all(), [
                'locations' => 'required',
                'price'=>'required',
                'age'=>'required',
                'description'=>'required'
            ]
        );

        if ($validator->fails()) {
            $response=array('status'=>'error','errors'=>implode(',', $validator->errors()->all()));
            return response()->json($response, 400);
        }else{
             // your code here ...
            $nursery->Where('description',  'LIKE', '%' . $request->input('description') . '%');
            $nursery->orWhere('name',  'LIKE', '%' . $request->input('description') . '%');
            // your code here ...
            return response()->json(['status'=>'success','result'=>$result],200);
        }

}