简单的php如果查询要仔细检查

Question

Is anything wrong with this code?

<?php

$variable = ;

if (isset($variable))

{

echo $variable ;
echo "also this" ;

}

else

echo "The variable is not set" ;

?>

also, the other potential value of the variable is :

$variable = <a href="http://www.mysite.com/article">This Article</a>;

To clarify, I have a variable that may hold one of two possible values : an a href tag with it's url, or notihng at all. I need to have two different printouts for each of these cases, maybe I'm not doing it the right way though!

Answer 1

In PHP you do not need to initialize a variable to check if it is set. The first line of your code is not only invalid, but also unnecessary.

Edit: Okay per your clarification in comments, the variable is always set, however it sometimes contains text and sometimes contains an empty string. In this case, I would do follow the advise by @prodigitalson in the comments:

if (isset($variable) && !empty($variable))
{
    // do set stuff here
}
else
{
    // not set, do blank stuff here
}