dsaeyrq451928 2019-05-07 08:39
浏览 124

PHP - 通过下载返回API调用者响应

I wrote an API call that saves and exports data to csv file in my Symfony project but I have trouble figuring out how to return the API caller response with download.

I want it to be like:

http://path.to.the.server/web/uploads/path/to/the/file.csv

My code:

 // get directory path to save csv files
    $rootDir = $this->container->get('kernel')->getRootDir();
    $dir = $rootDir . '/../web/uploads/';

    // make new directory by date
    if(!is_dir($dir)) {
        mkdir($dir, 0777, true) || chmod($dir, 0777);
    }

    // generating csv file name
    $fileName = 'name-'.date('Y-m-d').'.'.csv';
    $fp = fopen($dir . $fileName, 'w');

    // prepare data for exporting
    $getResults = $this->getMyData();
    $pullResults = json_decode($getResults);
    $results = $pullResults->data->items;

    $rows = [];

    $rows[] = array(
        "First Name",
        "Last Name"
    );

    foreach ($results as $row) {
        $rows[] = array(
            $row->firstName,
            $row->lastName
        );
    }

    foreach ($rows as $row) {
        fputcsv($fp, $row);
    }

    fclose($fp);

    return $this->success();

Any suggestions?

  • 写回答

1条回答 默认 最新

  • dongmeiran609914 2019-05-07 09:20
    关注

    This did it for me:

    $response = new BinaryFileResponse($dir .DIRECTORY_SEPARATOR. $fileName);
    
        $d = $response->headers->makeDisposition(
            ResponseHeaderBag::DISPOSITION_ATTACHMENT,
            $fileName
        );
    
        $response->headers->set('Content-Disposition', $d);
    
        return $response;
    

    Source: documentation

    评论

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