在AJAX调用中显示来自PHP的消息

Question

I have a favourites button calling an ajax request to update a MySQL database.

I would like to have a alert if there are duplicate additions or too many additions.

Can anybody see a way that I could show an alert if there is a duplicate addition? My code is below:

AJAX REQUEST

$.ajax({
    type: 'post',
    url: 'favaddDB.php',
    data: $('#addfaveform').serialize(),
    success: function () {
      alert('Added To Favourites');
    }
});

PHP

$db = new PDO("mysql:host=localhost;dbname=favourites", 'root', '');                                                                  
$query1="SELECT * FROM `$email` ";
$stat1=$db->prepare($query1);
$stat1->execute();// IMPORTANT add PDO variables here to make safe

//Check if fave adds >9 
$count = $stat1->rowCount();
$fave=$count;
if ($fave>9) {die(); exit();} // HERE I WISH TO RUN AN ALERT OR SEND BACK A MESSAGE TO DISPLAY
else {$fave=$fave+1;}

Answer 1

Just return the text to alert to your javascript:

$db = new PDO("mysql:host=localhost;dbname=favourites", 'root', '');                                                                  
$query1="Query here ($email/similar should NOT BE HERE! Add them via execute/prepare.";
$stat1=$db->prepare($query1);
$stat1->execute();// IMPORTANT add PDO variables here to make safe

//Check if fave adds >9 
$count = $stat1->rowCount();
$fave=$count;
if ($fave>9) {die("Here is a message");} // HERE I WISH TO RUN AN ALERT OR SEND BACK A MESSAGE TO DISPLAY
else {$fave=$fave+1; die("Here is another message"); }

Ajax request:

$.ajax({
  type: 'post',
  url: 'favaddDB.php',
  data: $('#addfaveform').serialize(),
  success: function (message) {
    alert(message);
  }
});

Additionally, you should consider using JSON, to pass back entire objects to your javascript, and parse it there:

$db = new PDO("mysql:host=localhost;dbname=favourites", 'root', '');                                                                  
$query1 = "Query here ($email/similar should NOT BE HERE! Add them via execute/prepare.";
$stat1 = $db->prepare($query1);
$result = $stat1->execute();// IMPORTANT add PDO variables here to make safe

// Tell javascript we're giving json.
header('Content-Type: application/json');

if (!$result) {
    echo json_encode(['error' => true, 'message' => 'A database error has occurred. Please try again later']);
    exit;
}

//Check if fave adds >9 
$count = $stat1->rowCount();
$fave = $count;
if ($fave > 9) {
    echo json_encode(['error' => false, 'fave' => $fave, 'message' => 'Fave > 9!']);
} // HERE I WISH TO RUN AN ALERT OR SEND BACK A MESSAGE TO DISPLAY
else {
   $fave = $fave+1;
   echo json_encode([
       'error' => false,
       'fave' => $fave,
       'message' => 'Current fave count: ' . $fave
   ]);
}

And in your ajax, make sure you set dataType: 'json', which will automatically parse it into an object:

$.ajax({
    type: 'post',
    url: 'favaddDB.php',
    data: $('#addfaveform').serialize(),
    dataType: 'JSON',
    success: function (res) {
        if (res.error) {
            //Display an alert or edit a div with an error message
            alert(res.message);
        } else {
            //Maybe update a div with the fave count
            document.getElementById('#favcount').value = res.fave;
            alert(res.message);
        }
    }
});