在if子句为真的时候迭代一个结果

Question

I have a condition that checks to see it the users id from the users table is the same as the user id that is attached to the post, and after that I want to attach a specific link for each post that meets that conditions with the actual posts data:

<?php if($post->user_id == $first):?>
                <?php foreach($code1 as $k=>$codes1): ?>
                <div class="imgSet">
                  <a href= "modify.php?1u=<?php echo $codes1->code;?>"> <!--hyperlink to edit text -->
                 <img src="img/settings.png"/> <!-- edit logo -->
                  <a/>
                </div>
                 <?php endforeach;?>
               <?php endif; ?>

Example: if $post->user_id== $first, my code will show all the value that $code gets from the database, I want to show one result at a time for each posts where the $post->user_id== $first.

To be more specific, if I have more posts with that meet the same condition in the if clause, I want to attach to that kink the code that is specific to that posts, but my program return for each condition meet all the result from the database.

Answer 1

You can use array_shift to get the first code from the codes array. All you have to assure is that you get the codes in the same order as the posts

<?php
foreach ($posts as $post) {
    if($post->user_id == $first) {
        $codes1 = array_shift($code1);
?>
<div class="imgSet">
    <a href="modify.php?1u=<?php echo $codes1->code;?>"> <!--hyperlink to edit text -->
        <img src="img/settings.png"/> <!-- edit logo -->
    <a/>
</div>
<?php
    }
}
?>