dongxidui1227 2016-08-21 06:20
浏览 18

尝试将类名作为字符串,名称空间问题传递时找不到类

Here is a method, in which a string is passed, using that string an instance is created. Example method:

public function action($actionType)
{
    //var_dump(new $actionType);

    if (!class_exists($actionType)) {
        //throw new Exception

    }

    if (!(new $actionType) instanceof ActionInterface) {
        ////throw new Exception
    }
    $actionType = new $actionType;
    echo $actionType->doAction();
}

But I am getting an error of class not found, however when I manually write the class name or manually append the namespace this way $actionType = __namespace__ . "\\$actionType";, then error goes. Why is that happening?

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1条回答 默认 最新

  • douzhi7451 2016-08-21 10:00
    关注

    Try this:

    public function action($actionType) {
         //var_dump(new $actionType);
         if (!class_exists($actionType)) {
           //throw new Exception
         }
         $actionType = new $actionType;
         if (!($actionType instanceof ActionInterface)) {
            ////throw new Exception
         }
    
         echo $actionType->doAction();
    }
    
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