douxiangbiao1899 2013-05-24 17:01
浏览 215
已采纳

php通过字符串名称调用类函数

How can I call a normal (not static) class function by its name?

The below gives an error saying param 1 needs to be a valid callback. I don't want the function to be static, I want it to be a normal function, and all the examples I've seen so far had them static.

class Player
{
    public function SayHi() { print("Hi"); }
}

$player = new Player();

call_user_func($Player, 'SayHi');
  • 写回答

5条回答 默认 最新

  • dongyi5070 2013-05-24 17:03
    关注

    The callback syntax is a little odd in PHP. What you need to do is make an array. The 1st element is the object, and the 2nd is the method.

    call_user_func(array($player, 'SayHi'));
    

    You can also do it without call_user_func:

    $player->{'SayHi'}();
    

    Or:

    $method = 'SayHi';
    $player->$method();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(4条)

报告相同问题?

悬赏问题

  • ¥15 stata安慰剂检验作图但是真实值不出现在图上
  • ¥15 c程序不知道为什么得不到结果
  • ¥40 复杂的限制性的商函数处理
  • ¥15 程序不包含适用于入口点的静态Main方法
  • ¥15 素材场景中光线烘焙后灯光失效
  • ¥15 请教一下各位,为什么我这个没有实现模拟点击
  • ¥15 执行 virtuoso 命令后,界面没有,cadence 启动不起来
  • ¥50 comfyui下连接animatediff节点生成视频质量非常差的原因
  • ¥20 有关区间dp的问题求解
  • ¥15 多电路系统共用电源的串扰问题