douzen3516 2016-07-18 09:38
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如何在CodeIgniter上实现登录的正确方法?

I'm practicing Codeigniter framework using a small project from my friends. Each pages need to load layout view and content view separately. The layout show users login info (logged or not, name, picture, etc.). The question is, how to show login info for each action efficiently? Most of the action will load the layout view, so i need to do that right.

I do implement a helper to get user model, but is that right?

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  • drhgzx4727 2016-07-18 10:00
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    You can use the following method:-

    In one separate model constructor function check the login details

    class Auth extends CI_Model {
    
        public function __construct(){
    
            parent::__construct();
    
            $this->load->model('loginModel');
    
            $this->load->library('session');
    
            if(!$this->loginModel->isLogin()){
    
                $this->session->sess_destroy();
    
                redirect('index.php/auth/login','refresh');
    
                exit;
    
            }
    
        }
    }
    

    Then in required controllers include the model in the controller constructor function

    class Main extends CI_Controller {
    
        public function __construct(){
            parent::__construct();      
            $this->load->model('auth');
        }
    
    } 
    

    No need to check all the controller action's if you added in the controller constructor it will check for all the actions

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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