I want to make a checkbox filter with PDO but I don't know how. After trying for quite some time and searching the internet, I still had no luck.
What I'm trying is to show all projects I made (which are taken from a database) and displaying them in a <div> called gallery. On the left is a bar called helpbar with the checkboxes (also taken from a database).
the websoft table includes all my projects, the filter table includes all filter options (like websites and apps).
<div class="container">
<div class="helpbar">
<div class="helpbar-block">
<?php $query=$db->prepare("SELECT * FROM `portfoliodb`.`filter`");
$query->execute();
while ( $row = $query->fetch()) {
$filter_id = $row['filter_id'];
$filter_name = $row ['filter_name'];
echo'<table class="helpbar-table">
<tr> <td><input type="checkbox" name ="websoft" checked class="filter-checkbox">'; echo htmlspecialchars($filter_name); echo'</td></tr>
</table>';
}?>
</div>
</div>
<div class="gallery">
<?php $query=$db->prepare("SELECT * FROM `portfoliodb`.`websoft`");
$query->execute();
while ( $row = $query->fetch()){
$websoft_id = $row['websoft_id'];
$websoft_name = $row ['websoft_name'];
$websoft_desc_en = $row ['websoft_desc_en'];
$websoft_img = $row ['websoft_img'];
$websoft_type = $row ['websoft_type'];
echo'<a><div class="gallery-item">
<p class="gallary-item-text">';
echo htmlspecialchars($websoft_name);
echo'</p></div></a>';
websoft_type basically means the filter (so if it's a website then websoft_type = website).
I hope you can make sense of the rather nooby code and help me out of my problem. Thank you for your time and answers.
--Edit--
It's no problem if the filter system isn't controlled from the DB if that makes it easier.
