dousuitang5239 2014-09-16 16:00
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PHP SQL查询服务器错误

I have a table as so:

  TABLE click_count
   (
   count int(3)
   );

which is currently an arbitrary number. I have this php script with an html button which should just increment the number by one. The SQL query works in php my admin but gets an error when it's ran on the page.

<?php

require("config.inc.php");

if(!empty($_POST)){

$query = "UPDATE click_count 
  SET count = count + :submit_1
  ";


    $query_params_ = array(
'submit_1' => $_POST['count']
);

try {
    // These two statements run the query against your database table. 
    $stmt   = $db->prepare($query);
    $result = $stmt->execute($query_params);
    }

 catch (PDOException $ex) {
    $response["message"] = "Database Error. Please Try Again!";
    die(json_encode($response));
    }

    $response["message"] = "Vote Cast!";
    echo json_encode($response);



} else {
?>    
<form action="vote.php" method="post"> 
Count:<br /> 
<input type="number" name="submit_1" value="1" /> 
<br /><br /> 

<input type="submit" value="Cast Vote" /> 
</form>

<?php
}

?>
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2条回答 默认 最新

  • duanlun2827 2014-09-16 16:07
    关注

    You have to change your array key to match the one in preparedStatement. Like this:

    $query_params_ = array(':submit_1' => $_POST['count']);
    

    Indeed, you are refering to $query_params in the execute() method, but you are defining $query_params_ (with underscore in the end).

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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