dtqi87613 2014-02-16 08:55
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注意:未定义的偏移量:0 ... 25

$score = 0;
$topics = array();
for ($i = 0; $i < count($user_responses); $i++) {
    if ( ((int)$user_responses[$i]['response'])+((int)$mismatch_responses[$i]['response']) == 3 ){
        $score += 1;
        array_push($topics, $user_responses[$i]['topic_name']);
    }
}

It's appear

Notice: Undefined offset: 0

Notice: Undefined offset: 1

Notice: Undefined offset: 2

....

Notice: Undefined offset: 25

can anybody help me?

Thanks...

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1条回答 默认 最新

  • doujiaoben28596 2014-02-16 09:00
    关注

    You can do two things in this case. Change the error reporting to 'E_ALL & ~E_NOTICE' so you won't be bothered with this messages. Or use the 'isset' function to check if a variable exists.

    I think you problem lays here:

    if ( ((int)$user_responses[$i]['response'])+((int)$mismatch_responses[$i]['response']) == 3 ){
    

    you should first check if both variables exists, and use it if they do:

    if (!isset($user_responses[$i]['response']) || !isset($mismatch_responses[$i]['response'])) continue; //skips the loop if one of the variables does not exist
    
    if ( ((int)$user_responses[$i]['response'])+((int)$mismatch_responses[$i]['response']) == 3 ){
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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