I'm having trouble getting my php search project working properly, having followed a guide, I don't fully understand the guide/code. My search bar will allow me to search for jobs in the database, but currently it shows all jobs and filters the one you search.
Is it possible to display these jobs as links, where it will take you to another page and display the currently selected job.
Here is my current code:
<?php
require 'config.php';
if(isset($_POST['search']))
{
$valueToSearch = $_POST['valueToSearch'];
// search in all table columns
// using concat mysql function
$query = "SELECT * FROM `job` WHERE CONCAT(`location`, `description`, `budget`, `duedate`,`title`) LIKE '%".$valueToSearch."%'";
$search_result = filterTable($query);
}
else {
$query = "SELECT * FROM `job`";
$search_result = filterTable($query);
}
// function to connect and execute the query
function filterTable($query)
{
$conn = mysqli_connect("localhost", "root", "", "bid4myjob");
$filter_Result = mysqli_query($conn, $query);
return $filter_Result;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>PHP HTML TABLE DATA SEARCH</title>
<style>
table,tr,th,td
{
border: 1px solid black;
}
</style>
</head>
<body>
<form action="php_html_table_data_filter.php" method="post">
<input type="text" name="valueToSearch" placeholder="Value To Search"><br><br>
<input type="submit" name="submit" value="Search"><br><br>
<table>
<tr>
<th>Title</th>
<th>Location</th>
<th>Description</th>
<th>Budget</th>
<th>Due date</th>
</tr>
<!-- populate table from mysql database -->
<?php while($row = mysqli_fetch_array($search_result)):?>
<tr>
<td><?php echo $row['title'];?></td>
<td><?php echo $row['location'];?></td>
<td><?php echo $row['description'];?></td>
<td><?php echo $row['budget'];?></td>
<td><?php echo $row['duedate'];?></td>
</tr>
<?php endwhile;?>
</table>
</form>
</body>
</html>
