How i can back to ajax request? for examplek I enter the webpage, start ajax request and progress bar is moving forwarde and for example I exit this page and back there, how to return to active/started ajax request ? how to not start this function again but if is running just back to this request.
that`s my ajax code:
<script>
jQuery(document).ready(function($) {
setTimeout(getProgress,100);
$('.stan').text('Pobieram analizę...');
$.urlParam = function(name){
var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
if (results==null){
return null;
}
else{
return decodeURI(results[1]) || 0;
}
}
var id = $.urlParam('id');
var idt = $.urlParam('idt');
$.ajax({
url: "views/getresults.php?id="+id+"&idt="+idt,
success: function(data) {
$("#loadresults").append(data);
}
});
setTimeout(getProgress,100);
return false;
function getProgress(){
$.ajax({
url: 'views/listen.php',
cache: false,
success: function(data) {
if(data<= 95 && data >= 0){
console.log(data);
$('#loadresults').html(data);
$('#progress').attr('aria-valuenow', data);
$('#progress').css('width', data + "%");
$('#progress').text(data + "%");
setTimeout(getProgress,1000);
console.log('Repeat');
}
else {
$('#progress').attr('aria-valuenow', 100);
$('#progress').css('width', 100 + "%");
$('#progress').text(100 + "%");
$('.stan').text('Dane zostały pobrane');
setTimeout(function(){
document.getElementById('progress').style.visibility = "hidden";
},1000);
setTimeout(function(){
document.getElementById('stan').style.visibility = "hidden";
},1200);
console.log('End');
}
}
});
}
});
</script>
