Ajax按钮php变量[关闭]

Question

I'm trying to make a ajax button to run a link with php code. In the code below when I click the button it gives a refresh on the page and does not run the line:

$.ajax({url: 'http://192.168.0.106:8080/v1/devices/'<?php $deviceID; ?>'/led/?access_token='<?php $dispositivo ?>'?params=l1,HIGH', success: function(result){

I want it to only run the line, without refreshing the entire page, where is the problem?

<?
echo "<form method='post' action='test.php'>";
?>

<script>
$(document).ready(function(){
    $("button").click(function(){
        $.ajax({url: 'http://192.168.0.106:8080/v1/devices/'<?php  $deviceID; ?>'/led/?access_token='<?php $dispositivo ?>'?params=l1,HIGH', success: function(result){
            $("#div1").html(result);
        }});
    });
});
</script>

<div id="div1"><h2>Let jQuery AJAX Change This Text</h2></div>

<button>Liga</button>
<?
     echo "</form>";//fim do formulário
?>

Answer 1

remove apostrophe (')

$.ajax({url: 'http://192.168.0.106:8080/v1/devices/<?php echo $deviceID; ?>/led/?access_token=<?php $dispositivo ?>?params=l1,HIGH', success: function(result){

or

$.ajax({url: 'http://192.168.0.106:8080/v1/devices/'+<?php echo $deviceID; ?>+'/led/?access_token=<?php $dispositivo ?>?params=l1,HIGH', success: function(result){

this string is Javascript string

'http://192.168.0.106:8080/v1/devices/'+<?php echo $deviceID; ?>+'/led/?access_token=<?php $dispositivo ?>?params=l1,HIGH'

and you must use echo to add php string to it.