无法在html中运行PHP脚本

Question

I have been trying to display contents between a <li> tag when my particular condition is satisfied. Initially I am having a $result string in which I am trying to check for a condition. But I suppose I am doing wrong with syntax. My code:

$Result1 =
'<div id="midrow">
 <ul class="rounded-list">
 <li ><strong>Name:</strong> '.$username.'</li>
     htmlspecialchars('<? if($tips_flag == 1){ ?>');
    <li >Competency 6 - Offer concessions: '.round($per_s6, 2).' percent</li>
     htmlspecialchars('<? } ?>)';
 </ul>
 </div>';

My these three lines are incorrect I suppose,

echo htmlspecialchars('<? if($tips_flag == 1){');
<li >Competency 6 - Offer concessions: '.round($per_s6, 2).' percent</li>
echo htmlspecialchars('<? } ?>)';

Help Plz!

Answer 1

I think this is what you are after (not sure about the htmlspecialchars though).

$html_additional_content = ($tips_flag == 1) ? '<li>Competency 6 - Offer concessions: ' . round($per_s6, 2) . ' percent</li>' : '';
$Result1 =
'<div id="midrow">
 <ul class="rounded-list">
 <li><strong>Name:</strong> '.$username.'</li>' . $html_additional_content .'
 </ul>
 </div>';

That first line is a conditional using the ternary operator. Also make sure your variables there are assigned.