Regular Exp在模式中找到重复短语2顺序单词

Question

I would like to catch 2 words sequentially duplicated in a pattern

I would like to be able to catch duplicate words in this case "cancer cervical" because they are the only duplicate 2 words sequentially.

pattern "cancer cervical diane mortality cervical cancer cervical diane sea"

I use this Regular expression but still can't catch 2 sequentially duplicated words.

/(\W|^)(.+)\s\2/ig

Answer 1

This should be able to do the job: /(\w+\s\w.*)\s.*\1/ if you are dealing with words including numbers.

var string = "cancer cervical diane mortality cervical cancer cervical diane sea";
var regex = /(\w+\s\w.*)\s.*\1/;
console.log(string.match(regex));

var string = "cancer cervical diane mortality cervical cancer cervical diane sea";
var string1=" this is a test cancer cervical cancer diane mortality cervical cancer cervical diane sea";
var string2=" test whether it will catch one word cancer mortality cervical cancer cervical diane sea";
var regex = /(\w+\s\w.*)\s.*\1/;
console.log(string.match(regex));
console.log(string1.match(regex));
console.log(string2.match(regex));

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