PHP响应。 第二个isset（）调用不起作用

Question

I have a simple PHP code that queries the DB and returns a list, which includes a new <kbd>submit</kbd> button, that will approve or not that post.

 if(isset($_POST['search'])){

while($row = mysqli_fetch_array($select)) {
  if($row['flag']==0) {
    echo "<br>";
    echo "<div class=\"dlcontainer2\">"; 
    echo "<div class=\"dlitem\">"; 
    echo "TourID: ";
    echo "<div class=\"dltourID\">{$row['tourID']}</div>"; 
    echo "Title: ";
    echo "<div class=\"dltitle\">{$row['title']}</div>"; 
    echo "City: ";
    echo "<div class=\"dlcity\">{$row['city']}</div>";
    echo "Description: ";
        echo "<div class=\"dldescription\">{$row['description']}</div>"; 
    //echo "<div class=\"dlapprove\">;
    echo "<input class=approve type='submit' name='submit' id=approve value='Approve'>"; 
    echo "</div>"; 
    echo "</div>"; 
    echo "<br>";

  }
}
}

And just below that, I make another isset() to see if the user clicks on the <kbd>Approve</kbd> button or not. But it is doing nothing:

if(isset($_POST['submit']) && !empty($_POST)) {
    echo "<script type='text/javascript'>alert('$message');</script>";
} else{
    echo "No true";
}

Answer 1

I think your problem isn't the isset() but the !empty($_POST) I don't believe that $_POST on it's own returns anything.

Instead maybe try using !empty($_POST['submit']) which does what it looks like your code is trying to do.