PHP函数作用域调用函数内的函数[关闭]

Question

I couldn't find anything regarding my issue while searching. Maybe I wasn't wording my search properly. Anyway, I the am trying to call a function from another file from inside another function, but it isn't working. It appears to be a scope issue. I have the following:

File1.php:

<?
function myCoolFunction()
{
    // Some really cool stuff in here
}

Then in File2.php:

<?
require('File1.php');

// A bunch of stuff

function anotherCoolFunction()
{
    // Do some stuff

    myCoolFunction();
}

myCoolFunction does not exist inside of anotherCoolFunction. I can call it in File2.php but not within another function. So my question is, how can this be achieved? Is there such thing as a super global function in php?

Thanks for any help!

Answer 1

For starters, use the function keyword to define functions.

When you require a file in the way that you are you are bringing its contents into the scope of the file you are in. (Files within a namespace are a different story.)

Think of your File2.php:

<?
require('File1.php');

// A bunch of stuff

function anotherCoolFunction()
{
    // Do some stuff

    myCoolFunction();
}

The same thing as doing:

<?
function myCoolFunction()
{
    // Some really cool stuff in here
}

// A bunch of stuff

function anotherCoolFunction()
{
    // Do some stuff

    myCoolFunction();
}

Lastly, (and I only say this because I don't see it in your code) make sure you call the encapsulating function. E.g.

$var = anotherCoolFunction();