dtn36013 2019-03-25 18:00
浏览 71

我正在尝试将AJAX应用到我的tbody而不是所有的表

  1. I'm trying to apply Ajax to my tbody only not all my table but I can't do this. The AJAX working good if I put my complete table in page. I want to split my table header & tbody to be in separated page. The following code is AJAX:

    function jsQueryData() {
var objData = {
    action: actionSplit0 + '/QueryData',
};

$.post(
    index_File,
    objData,
    function(data, status) {
        $('#table-container').html(data)
    },
    'html'
)

    }

  2. This is the code of my table. If I put the table code completely in one page the AJAX working good:

        <table class="table table-striped table-bordered table-hover 
       main-table-h">
      <thead>
        <tr>
          <td scope="col" class="search-th">
            <input type="text" name="" value=""> <!-- for search -->
          </td>
        </tr>
        <tr>
          <th scope="col" class="align-top">item no</th>
        </tr>
      </thead>
      <tbody>
        <?php foreach ($allData1 as $data): ?>
          <tr>
            <td><?=$data->{2}; ?></td>
          </tr>
        <?php endforeach; ?>
      </tbody>
    </table>

  3. I have tried to split the above code to be tbody in separate page but the data didn't come as a table but all tds come together.

  • 写回答

2条回答 默认 最新

  • drcvvkx914772 2019-03-25 18:41
    关注

    You will need to return ajax results as json. I did not see your table and database structure so let me create a table as follows and insert values into it for purpose of testing

    CREATE TABLE `users` (
  `id` int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
  `username` varchar(100) NOT NULL,
  `name` varchar(100) NOT NULL,
  `email` varchar(100) NOT NULL,
  `timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

    Insert Statetments for testing

    INSERT INTO `users` (`id`, `username`, `name`, `email`, `timestamp`) VALUES
(1, 'nancy1', 'Nancy moore  ', 'nancyfake@gmail.com', '2018-11-16 05:02:35'),
(2, 'tony1', 'tony moore    ', 'tonyfake@gmail.com', '2018-11-16 05:08:23');

    Here is a Re-write of your index.php reflecting ajax/jquery codes

    <!doctype html>
<html>
    <head>
        <title></title>

       <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <script type="text/javascript">
$(document).ready(function(){
    $.ajax({
        url: 'result.php',
        type: 'get',
        dataType: 'JSON',
        success: function(response){
            var len = response.length;
            for(var i=0; i<len; i++){
                var id = response[i].id;
                var username = response[i].username;
                var name = response[i].name;
                var email = response[i].email;

                var tr_str = "<tr>" +
                    "<td align='center'>" + (i+1) + "</td>" +
                    "<td align='center'>" + username + "</td>" +
                    "<td align='center'>" + name + "</td>" +
                    "<td align='center'>" + email + "</td>" +
                    "</tr>";

                $("#userTable tbody").append(tr_str);
            }

        }
    });
});
</script>

    </head>
    <body>
        <div class="container">
            <table id="userTable" border="1" >
                <thead>
                    <tr>
                        <th width="5%">S.no</th>
                        <th width="20%">Username</th>
                        <th width="20%">Name</th>
                        <th width="30%">Email</th>
                    </tr>
                </thead>
                <tbody></tbody>
            </table>
        </div>
    </body>
</html>

    config.php

    Remember to edit database credentials to suit yours

    <?php

$host = "localhost"; /* Host name */
$user = "root"; /* User */
$password = ""; /* Password */
$dbname = "your-db-name here"; /* Database name */

$con = mysqli_connect($host, $user, $password,$dbname);
// Check connection
if (!$con) {
 die("Connection failed: " . mysqli_connect_error());
}

    result.php

    <?php

include "config.php";

$return_arr = array();

$query = "SELECT * FROM users ORDER BY NAME";

$result = mysqli_query($con,$query);

while($row = mysqli_fetch_array($result)){
    $id = $row['id'];
    $username = $row['username'];
    $name = $row['name'];
    $email = $row['email'];

    $return_arr[] = array("id" => $id,
                    "username" => $username,
                    "name" => $name,
                    "email" => $email);
}

// Encoding array in JSON format
echo json_encode($return_arr);

    Thats all. Let me know how it goes

    评论

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