php代码在每第n次迭代后中断页面

Question

I am printing barcode on a page...from database...

I need to display only 6 barcode coupon on single page.

After that I need to break page.....and continue...till last row.

below is my code...but i cannot understand how to count and break page after every 6th row.

plz help me..

<?php foreach($data as $row) { ?>

<table  border="1px solid #666" summary="" width="48%" class="pos_fixed1">
<thead>

<tr>
<td>Receipt</td>
<td><?php echo htmlspecialchars($row['receipt_no']); ?></td>

<td>Coupon</td>
<td><?php echo htmlspecialchars($row['coupon']); ?></td>
</tr>
</thead>
</table>
<?php } ?>

Answer 1

Like mentioned in the comments, a good way around your problem would be to use pagination, as it means that you are giving users a way to still see this information. For quite a basic tutorial on this, I suggest looking here.

Alternatively, if you really need to use the approach you mentioned then something below may help you:

$count = count($data); //size of your array
$curr_count = 0; //will be used to increment each turn of loop
$show = 6; //how many pieces of data you want to show
foreach($data as $row) {
  $curr_count++;
  if($curr_count <= $show) {
    //show first 6 pieces of data
  } else if ($curr_count == $count) {
    //show last data
  } else {
    //do your page break
  }
}