doupu3211 2014-06-16 04:49 采纳率: 100%
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PHP date_format [关闭]

I have an array named $dataArray, i want to show all the array content in my View, but there's some problem when I echo the date. The error is:

date_format() expects parameter 1 to be DateTimeInterface, string given

Here's the code

foreach ($dataArray as $data){                                                          
   echo '<tr align="center">';
   echo '<td>';
   echo CHtml::encode($data->first_name);
   echo ' ';
   echo CHtml::encode($data->last_name);
   echo '</td>';
   echo '<td>';
   $date = ($data->join);
   echo date_format($date,'Y/m/d');
   echo '</td>';
   echo '<td>';
   echo CHtml::encode($data->last_login);
   echo '</td>';
   echo '<td>';
   echo '</tr>';
}
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2条回答 默认 最新

  • dongwei9771 2014-06-16 05:12
    关注

    In order to use date_format, you must first use the date_create() method. Take a look at the examples on that page for reference.

    $date = date_create($data->join);
    echo date_format($date, 'Y/m/d');
    

    OR

    You can also the native date() function

    $date = date('Y/m/d', strtotime($data->join));
    echo $date;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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